What is area x=-2,x=2,y=x,y=x^2-2 ?

The answer to area x=-2,x=2,y=x,y=x^2-2 is 19/3

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area x=-2,x=2,y=x,y=x^2-2

area

x = - 2, x = 2, y = x, y = x^{2} - 2

\frac{19}{3}

Decimal Notation

6.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x - (x^{2} - 2) d x

Solve

\int_{- 2}^{2} x - (x^{2} - 2) d x : \frac{19}{3}

The area is:

= \frac{19}{3}

y^{^{''}} + a y - b = 0

2 x^{5} + 3 y y^{^{'}} = 0

\int_{- 1}^{3} (- x^{2} + 2 x + 3) d x

\int \frac{1}{e ^{x}} d x

\int_{0}^{2} (8 t i - t^{3} j + 4 t^{7} k) d t

What is area x=-2,x=2,y=x,y=x^2-2 ?
The answer to area x=-2,x=2,y=x,y=x^2-2 is 19/3