What is the solution for (dy)/(dx)=(x^2y^2)/(1+2) ?

The solution for (dy)/(dx)=(x^2y^2)/(1+2) is y=-9/(x^3+c_{1)}

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(dy)/(dx)=(x^2y^2)/(1+2)

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + 2}

y = - \frac{9}{x ^{3} + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + 2}

Solve separable ODE:

y = - \frac{9}{x ^{3} + c _{1}}

y = - \frac{9}{x ^{3} + c _{1}}

\int \frac{7 - 98 x}{9 - 49 x ^{2}} d x

y = 5 + 4 x^{2} - 2 x^{3}

x^{2} + 4 x - 3

3.5 x - 2 x^{2}

\int \frac{1 - 2 x}{x + 1} d x

What is the solution for (dy)/(dx)=(x^2y^2)/(1+2) ?
The solution for (dy)/(dx)=(x^2y^2)/(1+2) is y=-9/(x^3+c_{1)}