What is the derivative of 4e^{-2x} ?

The derivative of 4e^{-2x} is -8e^{-2x}

What is the first derivative of 4e^{-2x} ?

The first derivative of 4e^{-2x} is -8e^{-2x}

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\frac{d}{d x} (4 e^{- 2 x})

- 8 e^{- 2 x}

Solution steps

\frac{d}{d x} (4 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 4 e^{- 2 x} (- 2)

Simplify

= - 8 e^{- 2 x}

\int \frac{cos ( t )}{t} d t

\int \frac{1}{( cos ( 4 x ) ) ^{2}} d x

\int (x^{2} + 9) e^{- x} d x

\int \frac{π y ^{4}}{16} d y

f (x) = - 2 cos (x)

What is the derivative of 4e^{-2x} ?
The derivative of 4e^{-2x} is -8e^{-2x}
What is the first derivative of 4e^{-2x} ?
The first derivative of 4e^{-2x} is -8e^{-2x}