What is the integral of 4cos(x) ?

The integral of 4cos(x) is 4sin(x)+C

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integral of 4cos(x)

\int 4 cos (x) d x

4 sin (x) + C

Solution steps

\int 4 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 4 sin (x)

Add a constant to the solution

= 4 sin (x) + C

\int \frac{1}{22 - x ^{2}} d x

n = 0 \sum \infty 6 (\frac{1}{7})^{n}

x \to 2 - lim (\frac{x + 2}{x - 4})

n = - \infty \sum \infty 7^{2}

x \to 2 lim (\frac{3 x}{x - 4})