What is the integral from 0 to pi of sin^2(x)cos(x) ?

The integral from 0 to pi of sin^2(x)cos(x) is 0

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integral from 0 to pi of sin^2(x)cos(x)

\int_{0}^{π} sin^{2} (x) cos (x) d x

0

Solution steps

\int_{0}^{π} sin^{2} (x) cos (x) d x

Compute the indefinite integral:

\int sin^{2} (x) cos (x) d x = \frac{sin ^{3} ( x )}{3} + C

Compute the boundaries:

\int_{0}^{π} sin^{2} (x) cos (x) d x = 0 - 0

= 0 - 0

Simplify

= 0

f (x) = (6 x - 5)^{\frac{1}{2}}, at x = 1

\frac{d y}{d x} = 8 x^{- 9}

\frac{d}{d x} (\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}})

y = sin (tan (5 x))

\int (t^{9} + 4 t) (9 t^{8} + 4) d t

What is the integral from 0 to pi of sin^2(x)cos(x) ?
The integral from 0 to pi of sin^2(x)cos(x) is 0