What is the d/(dy)(2sqrt(4-y)) ?

The d/(dy)(2sqrt(4-y)) is -1/(sqrt(4-y))

What is the first d/(dy)(2sqrt(4-y)) ?

The first d/(dy)(2sqrt(4-y)) is -1/(sqrt(4-y))

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\frac{d}{d y} (2 4 - y)

- \frac{1}{4 - y}

Solution steps

\frac{d}{d y} (2 4 - y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d y} (4 - y)

Apply the chain rule:

\frac{1}{2 4 - y} \frac{d}{d y} (4 - y)

= \frac{1}{2 4 - y} \frac{d}{d y} (4 - y)

\frac{d}{d y} (4 - y) = - 1

= 2 \cdot \frac{1}{2 4 - y} (- 1)

Simplify

2 \cdot \frac{1}{2 4 - y} (- 1) : - \frac{1}{4 - y}

= - \frac{1}{4 - y}

\int \frac{5}{( x - 2 ) ^{2}} d x

\frac{d}{d x} (2 sec (x))

y = 1 + e^{- 2 x^{2} + 8 x - 7}

x \to 0 lim (- (\frac{1}{x ^{2}}))

y^{^{'}} = 9 t y^{2}

What is the d/(dy)(2sqrt(4-y)) ?
The d/(dy)(2sqrt(4-y)) is -1/(sqrt(4-y))
What is the first d/(dy)(2sqrt(4-y)) ?
The first d/(dy)(2sqrt(4-y)) is -1/(sqrt(4-y))