What is derivative of f(x)=sqrt((y-1)/3) ?

The answer to derivative of f(x)=sqrt((y-1)/3) is (dy)/(dx)=0

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derivative of f(x)=sqrt((y-1)/3)

derivative of

f (x) = \frac{y - 1}{3}

\frac{d y}{d x} = 0

Solution steps

f (x) = \frac{y - 1}{3}

Treat

y

y (x)

Differentiate both sides:

0 = \frac{\frac{d y}{d x}}{2 3 y - 1}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 0

\frac{d y}{d x} = 0

\frac{d}{d x} (\frac{5}{x} ln (x))

(tan (3 x))^{^{'}}

\int_{1}^{2} (1 - x^{2}) - (3 - 3 x) d x

\frac{d x}{d t} = x^{2} - 6 x + 14

f (x) = 2 x^{4} + x^{3} - x^{2} + 4

What is derivative of f(x)=sqrt((y-1)/3) ?
The answer to derivative of f(x)=sqrt((y-1)/3) is (dy)/(dx)=0