What is the integral of (7x^6+7x^3+4) ?

The integral of (7x^6+7x^3+4) is x^7+(7x^4)/4+4x+C

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integral of (7x^6+7x^3+4)

\int (7 x^{6} + 7 x^{3} + 4) d x

x^{7} + \frac{7 x ^{4}}{4} + 4 x + C

Solution steps

\int 7 x^{6} + 7 x^{3} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 x^{6} d x + \int 7 x^{3} d x + \int 4 d x

\int 7 x^{6} d x = x^{7}

\int 7 x^{3} d x = \frac{7 x ^{4}}{4}

\int 4 d x = 4 x

= x^{7} + \frac{7 x ^{4}}{4} + 4 x

Add a constant to the solution

= x^{7} + \frac{7 x ^{4}}{4} + 4 x + C

\int e^{l n (x^{2})} x d x

\frac{d}{d x} (e^{2 x} - cos (2 x))

x \to 0 lim (\frac{( sin ( 4 x ) )}{x})

\int - 3 sin (5 x) cos^{2} (5 x) d x

x \to 0 lim (5 x)

What is the integral of (7x^6+7x^3+4) ?
The integral of (7x^6+7x^3+4) is x^7+(7x^4)/4+4x+C