What is the derivative of (x^2-81/(x-9)) ?

The derivative of (x^2-81/(x-9)) is 1

What is the first derivative of (x^2-81/(x-9)) ?

The first derivative of (x^2-81/(x-9)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 81}{x - 9})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 81}{x - 9})

Simplify

\frac{x ^{2} - 81}{x - 9} : x + 9

= \frac{d}{d x} (x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (9)

\frac{d x}{d x} = 1

\frac{d}{d x} (9) = 0

= 1 + 0

Simplify

= 1

\frac{1}{x ^{3}}

\frac{\partial}{\partial y} (2 x y^{2} + 3 x^{2})

f (x) = 8^{x}

(2 x - 3)^{3} (x^{4} + 1)^{2}

y^{^{''}} + b \cdot y = 0

What is the derivative of (x^2-81/(x-9)) ?
The derivative of (x^2-81/(x-9)) is 1
What is the first derivative of (x^2-81/(x-9)) ?
The first derivative of (x^2-81/(x-9)) is 1