What is (\partial)/(\partial v)(w^2sin(v)) ?

The answer to (\partial)/(\partial v)(w^2sin(v)) is w^2cos(v)

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(\partial)/(\partial v)(w^2sin(v))

\frac{\partial}{\partial v} (w^{2} sin (v))

w^{2} cos (v)

Solution steps

\frac{\partial}{\partial v} (w^{2} sin (v))

Treat

w

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= w^{2} \frac{\partial}{\partial v} (sin (v))

Apply the common derivative:

\frac{\partial}{\partial v} (sin (v)) = cos (v)

= w^{2} cos (v)

\int 21 + 4 x - x^{2} d x

x \to 4 lim (\frac{3 x - 12}{x - 4})

y = 2 x^{2} + 10, y = 4 x + 16

(x^{9} - x^{\frac{1}{6}}) 6^{x}

t \to π lim (cos (t))

What is (\partial)/(\partial v)(w^2sin(v)) ?
The answer to (\partial)/(\partial v)(w^2sin(v)) is w^2cos(v)