What is the derivative of e^{x+1}-1 ?

The derivative of e^{x+1}-1 is e^{x+1}

What is the first derivative of e^{x+1}-1 ?

The first derivative of e^{x+1}-1 is e^{x+1}

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\frac{d}{d x} (e^{x + 1} - 1)

e^{x + 1}

Solution steps

\frac{d}{d x} (e^{x + 1} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x + 1}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{x + 1}) = e^{x + 1}

\frac{d}{d x} (1) = 0

= e^{x + 1} - 0

Simplify

= e^{x + 1}

f (x) = 5 x cos (x), at x = π

f (x) = (x^{x} + 1)^{2}

\frac{d}{d x} ((2 x - 1) (x^{2} - 6 x + 3))

\frac{d y}{d t} = \frac{1}{1 + y}

\int 1 + sin (2 x) d x

What is the derivative of e^{x+1}-1 ?
The derivative of e^{x+1}-1 is e^{x+1}
What is the first derivative of e^{x+1}-1 ?
The first derivative of e^{x+1}-1 is e^{x+1}