What is area y=xsqrt(9-x^2),y=0,x=0,x=3 ?

The answer to area y=xsqrt(9-x^2),y=0,x=0,x=3 is 9

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area y=xsqrt(9-x^2),y=0,x=0,x=3

area

y = x 9 - x^{2}, y = 0, x = 0, x = 3

9

Solution steps

Apply the area formula:

\int_{0}^{3} ∣ x ∣ - x^{2} + 9 d x

Solve

\int_{0}^{3} ∣ x ∣ - x^{2} + 9 d x : 9

The area is:

= 9

\frac{d}{d x} (arccos (6 x))

\int x^{3} \cdot ln (x) d x

\int_{1}^{e} \frac{9 x ^{2} + 9 x + 9}{x} d x

\int \frac{1}{6} d x

\frac{\partial}{\partial x} (6 x^{2} - 4 x y^{2})

What is area y=xsqrt(9-x^2),y=0,x=0,x=3 ?
The answer to area y=xsqrt(9-x^2),y=0,x=0,x=3 is 9