What is the limit as x approaches 0-of x^2cos(1/x) ?

The limit as x approaches 0-of x^2cos(1/x) is 0

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limit as x approaches 0-of x^2cos(1/x)

x \to 0 - lim (x^{2} cos (\frac{1}{x}))

0

Solution steps

x \to 0 - lim (x^{2} cos (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\frac{\partial}{\partial x} (x^{2} z + y, x + y, y + z^{2})

4 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 9 x e^{- y}

x^{2} - 2 x + 3

f (x) = \frac{3 x}{x ^{2} - 6}, 3, at x = 3

\frac{8 5}{15} x^{\frac{3}{2}} - 2

What is the limit as x approaches 0-of x^2cos(1/x) ?
The limit as x approaches 0-of x^2cos(1/x) is 0