What is the solution for (dy}{dx}=\frac{2x^2)/y ?

The solution for (dy}{dx}=\frac{2x^2)/y is y=sqrt((4x^3)/3+c_{1)},y=-sqrt((4x^3)/3+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{2x^2)/y

\frac{d y}{d x} = \frac{2 x ^{2}}{y}

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 x ^{2}}{y}

Solve separable ODE:

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

\frac{d}{d x} (2 x^{\frac{2}{3}})

2 + 3 x

\frac{d}{d x} (- 9 sin (3 x))

\frac{d}{d x} (tan (π - \frac{9}{x}))

\frac{d}{d x} (9 x^{9} e^{x - 1})

What is the solution for (dy}{dx}=\frac{2x^2)/y ?
The solution for (dy}{dx}=\frac{2x^2)/y is y=sqrt((4x^3)/3+c_{1)},y=-sqrt((4x^3)/3+c_{1)}