What is the derivative of sqrt(3/x) ?

The derivative of sqrt(3/x) is -(sqrt(3))/(2x^{3/2)}

What is the first derivative of sqrt(3/x) ?

The first derivative of sqrt(3/x) is -(sqrt(3))/(2x^{3/2)}

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derivative of

\frac{3}{x}

- \frac{3}{2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{x})

Apply the chain rule:

\frac{1}{2 \frac{3}{x}} \frac{d}{d x} (\frac{3}{x})

= \frac{1}{2 \frac{3}{x}} \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= \frac{1}{2 \frac{3}{x}} (- \frac{3}{x ^{2}})

Simplify

\frac{1}{2 \frac{3}{x}} (- \frac{3}{x ^{2}}) : - \frac{3}{2 x ^{\frac{3}{2}}}

= - \frac{3}{2 x ^{\frac{3}{2}}}

f (x) = x^{3} - 2 x + 1

- 3 sin (2 t)

\int x^{\frac{3}{2}} + 2 x + 1 d x

x y^{^{'}} + y = 32 x

\int ∣ x - 4 ∣ d x

What is the derivative of sqrt(3/x) ?
The derivative of sqrt(3/x) is -(sqrt(3))/(2x^{3/2)}
What is the first derivative of sqrt(3/x) ?
The first derivative of sqrt(3/x) is -(sqrt(3))/(2x^{3/2)}