What is the integral from 0 to 7 of sqrt(y+9) ?

The integral from 0 to 7 of sqrt(y+9) is 74/3

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integral from 0 to 7 of sqrt(y+9)

\int_{0}^{7} y + 9 d y

\frac{74}{3}

Decimal

24.66666 \dots

Solution steps

\int_{0}^{7} y + 9 d y

Apply u-substitution

: \int_{9}^{16} u d u

= \int_{9}^{16} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{16}

= [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{16}

Compute the boundaries:

\frac{74}{3}

= \frac{74}{3}

f (x) = 2 sin (x), at x = \frac{π}{6}

y = x, y = \frac{1}{2} x, x = 9

\int cos^{3} (\frac{x}{14}) d x

\frac{\partial}{\partial x} (e^{5 x yz - 6})

\int 1 + 3 x^{2} y^{2} d y

What is the integral from 0 to 7 of sqrt(y+9) ?
The integral from 0 to 7 of sqrt(y+9) is 74/3