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Popular >

2xydx=(1+y)dy

Solution

2 x y d x = (1 + y) d y

Solution

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

Solution steps

2 x y d x = (1 + y) d y

Solve separable ODE:

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

Popular Examples

(\partial)/(\partial y)(x^3-3xy^2+y^3)

\frac{\partial}{\partial y} (x^{3} - 3 x y^{2} + y^{3})

derivative of f(x)=(2t+3)/(t+5)derivative of

f (x) = \frac{2 t + 3}{t + 5}

(d^2)/(dx^2)(te^{-t})

\frac{d ^{2}}{d x ^{2}} (t e^{- t})

integral of sqrt(x-2x)

\int x - 2 x d x

tangent of y=-2x^3,(-1,2)tangent of

y = - 2 x^{3}, (- 1, 2)

Frequently Asked Questions (FAQ)

What is the solution for 2xydx=(1+y)dy ?
The solution for 2xydx=(1+y)dy is y=\W(1/(e^{-x^2-c_{1)}})