What is the solution for (dy)/(dx)=(x^2+2y^2)/(xy) ?

The solution for (dy)/(dx)=(x^2+2y^2)/(xy) is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}

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(dy)/(dx)=(x^2+2y^2)/(xy)

\frac{d y}{d x} = \frac{x ^{2} + 2 y ^{2}}{x y}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + 2 y ^{2}}{x y}

Solve Bernoulli ODE:

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

f (x) = \frac{1}{( x - 5 )}, at x = - 3

\frac{2 s + 1}{s ^{2} - 2 s + 2}

\int_{2}^{3} 3 x^{2} d x

2 x + 3

\frac{d}{d x} ((1 + 1 0^{l n (x)})^{6})

What is the solution for (dy)/(dx)=(x^2+2y^2)/(xy) ?
The solution for (dy)/(dx)=(x^2+2y^2)/(xy) is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}