What is the tangent of f(x)=4-x^2,\at x=1.154 ?

The tangent of f(x)=4-x^2,\at x=1.154 is y=-2.308x+5.331716

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tangent of f(x)=4-x^2,\at x=1.154

tangent of

f (x) = 4 - x^{2}, at x = 1.154

y = - 2.308 x + 5.331716

Solution steps

Find the tangent point:

(1.154, 2.668284)

Find the slope of

f (x) = 4 - x^{2} : \frac{df ( x )}{d x} = - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2.308

Find the line with slope m=

- 2.308

and passing through

(1.154, 2.668284) : y = - 2.308 x + 5.331716

y = - 2.308 x + 5.331716

x^{3} - 3 x^{2} + 2 x - 2, at x = 0

\frac{\partial}{\partial x} (\frac{1}{x ^{2} + 2 y})

y = \frac{1}{2 x - 9}

\frac{d}{d x} (e^{- i x})

x \to 0 lim ((1 + x) \frac{1}{x})

What is the tangent of f(x)=4-x^2,\at x=1.154 ?
The tangent of f(x)=4-x^2,\at x=1.154 is y=-2.308x+5.331716