What is the solution for (dy)/(dx)=(e^x-e^{-x})^2 ?

The solution for (dy)/(dx)=(e^x-e^{-x})^2 is y=-2x+sinh(2x)+c_{1}

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(dy)/(dx)=(e^x-e^{-x})^2

\frac{d y}{d x} = (e^{x} - e^{- x})^{2}

y = - 2 x + sinh (2 x) + c_{1}

Solution steps

\frac{d y}{d x} = (e^{x} - e^{- x})^{2}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = (e^{x} - e^{- x})^{2}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (e^{x} - e^{- x})^{2} d x

\int (e^{x} - e^{- x})^{2} d x = - 2 x + sinh (2 x) + c_{1}

y = - 2 x + sinh (2 x) + c_{1}

f (x) = x^{2}, (0, - 9)

sin (θ) + cos (θ)

\frac{d}{d x} (2 sec (x) tan (x))

arctan (x), 0

\int \frac{e ^{c o s (x)}}{csc ( x )} d x

What is the solution for (dy)/(dx)=(e^x-e^{-x})^2 ?
The solution for (dy)/(dx)=(e^x-e^{-x})^2 is y=-2x+sinh(2x)+c_{1}