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Popular >

integral from 1 to 4 of (3x^2+1)

Solution

\int_{1}^{4} (3 x^{2} + 1) d x

Solution

66

Solution steps

\int_{1}^{4} 3 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 3 x^{2} d x + \int_{1}^{4} 1 d x

\int_{1}^{4} 3 x^{2} d x = 63

\int_{1}^{4} 1 d x = 3

= 63 + 3

Simplify

= 66

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (3x^2+1) ?
The integral from 1 to 4 of (3x^2+1) is 66