What is the derivative of (cos(ln(x)))/x ?

The derivative of (cos(ln(x)))/x is (-sin(ln(x))-cos(ln(x)))/(x^2)

What is the first derivative of (cos(ln(x)))/x ?

The first derivative of (cos(ln(x)))/x is (-sin(ln(x))-cos(ln(x)))/(x^2)

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derivative of

\frac{cos ( ln ( x ) )}{x}

\frac{- sin ( ln ( x ) ) - cos ( ln ( x ) )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{cos ( ln ( x ) )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( cos ( ln ( x ) ) ) x - \frac{d x}{d x} cos ( ln ( x ) )}{x ^{2}}

\frac{d}{d x} (cos (ln (x))) = - \frac{sin ( ln ( x ) )}{x}

\frac{d x}{d x} = 1

= \frac{( - \frac{s i n ( l n ( x ) )}{x} ) x - 1 \cdot cos ( ln ( x ) )}{x ^{2}}

Simplify

\frac{( - \frac{s i n ( l n ( x ) )}{x} ) x - 1 \cdot cos ( ln ( x ) )}{x ^{2}} : \frac{- sin ( ln ( x ) ) - cos ( ln ( x ) )}{x ^{2}}

= \frac{- sin ( ln ( x ) ) - cos ( ln ( x ) )}{x ^{2}}

\int \frac{x + 1}{x} d x

y^{^{'}} = 4 y^{2} + 1

\int cos (k) x d x

\int (x^{2} + 2 x) cos (x^{3} + 3 x^{2} - 47) d x

What is the derivative of (cos(ln(x)))/x ?
The derivative of (cos(ln(x)))/x is (-sin(ln(x))-cos(ln(x)))/(x^2)
What is the first derivative of (cos(ln(x)))/x ?
The first derivative of (cos(ln(x)))/x is (-sin(ln(x))-cos(ln(x)))/(x^2)