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Popular >

y^'=4y^2+1

Solution

y^{^{'}} = 4 y^{2} + 1

Solution

y = \frac{tan ( 2 t + c _{1} )}{2}

Solution steps

y^{'} (t) = 4 y^{2} + 1

Solve separable ODE:

y = \frac{tan ( 2 t + c _{1} )}{2}

y = \frac{tan ( 2 t + c _{1} )}{2}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=4y^2+1 ?
The solution for y^'=4y^2+1 is y=(tan(2t+c_{1}))/2