What is the normal of g(x)=x^4-6/x ,(2,13) ?

The normal of g(x)=x^4-6/x ,(2,13) is g(x)=-2/67 x+875/67

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normal of g(x)=x^4-6/x ,(2,13)

normal of

g (x) = x^{4} - \frac{6}{x}, (2, 13)

g (x) = - \frac{2}{67} x + \frac{875}{67}

Solution steps

Find the slope of

g (x) = x^{4} - \frac{6}{x} : \frac{d g ( x )}{d x} = 4 x^{3} + \frac{6}{x ^{2}}

Compute the slope of

g (x) = x^{4} - \frac{6}{x}

(2, 13) : m = \frac{67}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{67}

Find the line with slope m=

- \frac{2}{67}

and passing through

(2, 13) : g (x) = - \frac{2}{67} x + \frac{875}{67}

g (x) = - \frac{2}{67} x + \frac{875}{67}

4 cot^{7} (x), at x = \frac{π}{4}

\frac{\partial}{\partial y} (2 y^{2} x)

x \to 8 lim (\frac{3 x ^{2} - 24 x}{x ^{2} - 64})

x \to 2 lim (\frac{( x + 1 )}{x - 2})

\frac{d}{d x} (2 x - sin (2 x))

What is the normal of g(x)=x^4-6/x ,(2,13) ?
The normal of g(x)=x^4-6/x ,(2,13) is g(x)=-2/67 x+875/67