What is the integral of x/(sqrt(y)) ?

The integral of x/(sqrt(y)) is 2xsqrt(y)+C

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integral of x/(sqrt(y))

\int \frac{x}{y} d y

2 x y + C

Solution steps

\int \frac{x}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x \cdot \int \frac{1}{y} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= x \cdot 2 y^{\frac{1}{2}}

Apply radical rule:

= 2 x y

Add a constant to the solution

= 2 x y + C

n = 0 \sum \infty \frac{- 1 ^{n}}{n !}

y = x^{10} + 1 + 1 - x

\frac{d}{d x} (9 x + 4)

\int (4 sec (x) tan (x) - 2 sec^{2} (x)) d x

\int 10 25 - x d x

What is the integral of x/(sqrt(y)) ?
The integral of x/(sqrt(y)) is 2xsqrt(y)+C