What is the derivative of 2x^3+x^2 ?

The derivative of 2x^3+x^2 is 6x^2+2x

What is the first derivative of 2x^3+x^2 ?

The first derivative of 2x^3+x^2 is 6x^2+2x

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\frac{d}{d x} (2 x^{3} + x^{2})

6 x^{2} + 2 x

Solution steps

\frac{d}{d x} (2 x^{3} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 6 x^{2} + 2 x

y^{^{'}} = - y^{2}

\frac{d}{d t} (A t e^{- 4 t})

\int_{2}^{3} \frac{12}{3 - x} d x

\int \frac{x}{x ^{3} + 1} d x

x \to 0 lim (\frac{3 ^{x} - 1 0 ^{x}}{x})

What is the derivative of 2x^3+x^2 ?
The derivative of 2x^3+x^2 is 6x^2+2x
What is the first derivative of 2x^3+x^2 ?
The first derivative of 2x^3+x^2 is 6x^2+2x