What is (\partial)/(\partial x)(sin(3x+4y)) ?

The answer to (\partial)/(\partial x)(sin(3x+4y)) is cos(3x+4y)*3

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(\partial)/(\partial x)(sin(3x+4y))

\frac{\partial}{\partial x} (sin (3 x + 4 y))

cos (3 x + 4 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x + 4 y))

Treat

y

as a constant

Apply the chain rule:

cos (3 x + 4 y) \frac{\partial}{\partial x} (3 x + 4 y)

= cos (3 x + 4 y) \frac{\partial}{\partial x} (3 x + 4 y)

\frac{\partial}{\partial x} (3 x + 4 y) = 3

= cos (3 x + 4 y) \cdot 3

(4 x + 7)^{2}

\int \frac{1}{2 - x ^{2}} d x

\frac{d}{d x} (\frac{x + 4}{x - 1})

\frac{d}{d x} (ln (5 x + 2))

x + 12

What is (\partial)/(\partial x)(sin(3x+4y)) ?
The answer to (\partial)/(\partial x)(sin(3x+4y)) is cos(3x+4y)*3