What is the derivative of f(x)=\sqrt[3]{x-8} ?

The derivative of f(x)=\sqrt[3]{x-8} is 1/(3(x-8)^{2/3)}

What is the first derivative of f(x)=\sqrt[3]{x-8} ?

The first derivative of f(x)=\sqrt[3]{x-8} is 1/(3(x-8)^{2/3)}

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derivative of

\frac{1}{3 ( x - 8 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x - 8 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 8)

= \frac{1}{3 ( x - 8 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 8)

\frac{d}{d x} (x - 8) = 1

= \frac{1}{3 ( x - 8 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x - 8 ) ^{\frac{2}{3}}}

x \to 3 lim (\frac{∣ x - 3 ∣}{3 - x})

\int (1 - 2 x) e^{- 2 x} d x

\frac{3}{y}

e^{p}

What is the derivative of f(x)=\sqrt[3]{x-8} ?
The derivative of f(x)=\sqrt[3]{x-8} is 1/(3(x-8)^{2/3)}
What is the first derivative of f(x)=\sqrt[3]{x-8} ?
The first derivative of f(x)=\sqrt[3]{x-8} is 1/(3(x-8)^{2/3)}