What is the derivative of 2/(x^2+3) ?

The derivative of 2/(x^2+3) is -(4x)/((x^2+3)^2)

What is the first derivative of 2/(x^2+3) ?

The first derivative of 2/(x^2+3) is -(4x)/((x^2+3)^2)

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derivative of

\frac{2}{x ^{2} + 3}

- \frac{4 x}{( x ^{2} + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{2} + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x ^{2} + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x^{2} + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 3 ) ^{2}} \frac{d}{d x} (x^{2} + 3)

= - \frac{1}{( x ^{2} + 3 ) ^{2}} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= 2 (- \frac{1}{( x ^{2} + 3 ) ^{2}} \cdot 2 x)

Simplify

2 (- \frac{1}{( x ^{2} + 3 ) ^{2}} \cdot 2 x) : - \frac{4 x}{( x ^{2} + 3 ) ^{2}}

= - \frac{4 x}{( x ^{2} + 3 ) ^{2}}

2 a x + b

\frac{d y}{d x} = \frac{2 x}{y}

\int_{- 8}^{8} x^{\frac{1}{3}} d x

y^{^{''}} - \frac{1}{x} y^{^{'}} = 3 x

\int_{1}^{4} x^{3} d x

What is the derivative of 2/(x^2+3) ?
The derivative of 2/(x^2+3) is -(4x)/((x^2+3)^2)
What is the first derivative of 2/(x^2+3) ?
The first derivative of 2/(x^2+3) is -(4x)/((x^2+3)^2)