What is the sum from n=1 to infinity of n(3/2)^n ?

The sum from n=1 to infinity of n(3/2)^n is diverges

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sum from n=1 to infinity of n(3/2)^n

n = 1 \sum \infty n (\frac{3}{2})^{n}

diverges

Solution steps

n = 1 \sum \infty n (\frac{3}{2})^{n}

Apply Series Ratio Test:

diverges

= diverges

\frac{d}{d x} ((\frac{x ^{2} + 1}{x ^{2} - 1})^{4})

y = cos (\frac{π t}{2} - \frac{π}{3})

h \to 0 lim (\frac{1 - cos ( 7 h )}{h})

- 2 x^{2} + 2 x

x \to 6 lim (21 x + 18)

What is the sum from n=1 to infinity of n(3/2)^n ?
The sum from n=1 to infinity of n(3/2)^n is diverges