What is the derivative of f(x)= 2/(x-3) ?

The derivative of f(x)= 2/(x-3) is -2/((x-3)^2)

What is the first derivative of f(x)= 2/(x-3) ?

The first derivative of f(x)= 2/(x-3) is -2/((x-3)^2)

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derivative of

f (x) = \frac{2}{x - 3}

- \frac{2}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

= - \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= 2 (- \frac{1}{( x - 3 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( x - 3 ) ^{2}} \cdot 1) : - \frac{2}{( x - 3 ) ^{2}}

= - \frac{2}{( x - 3 ) ^{2}}

y = 1 - x^{2}, at x = \frac{1}{2}

x \to 9 lim (\frac{( 16 + x )}{16 + x})

f (x) = e^{\frac{x}{2}}

{\frac{( s + 1 ) ^{2}}{s ^{3}}}

y^{^{'}} = \frac{x y ^{3}}{25}

What is the derivative of f(x)= 2/(x-3) ?
The derivative of f(x)= 2/(x-3) is -2/((x-3)^2)
What is the first derivative of f(x)= 2/(x-3) ?
The first derivative of f(x)= 2/(x-3) is -2/((x-3)^2)