What is (\partial)/(\partial x)(3e^{xy+4}) ?

The answer to (\partial)/(\partial x)(3e^{xy+4}) is 3e^{xy+4}y

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(\partial)/(\partial x)(3e^{xy+4})

\frac{\partial}{\partial x} (3 e^{x y + 4})

3 e^{x y + 4} y

Solution steps

\frac{\partial}{\partial x} (3 e^{x y + 4})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (e^{x y + 4})

Apply the chain rule:

e^{x y + 4} \frac{\partial}{\partial x} (x y + 4)

= e^{x y + 4} \frac{\partial}{\partial x} (x y + 4)

\frac{\partial}{\partial x} (x y + 4) = y

= 3 e^{x y + 4} y

\frac{d y}{d x} = x y + 5 x + 2 y + 10

13 sin (2 t)

\int (\frac{10}{1 - sin ^{2} ( x )}) d x

n = 1 \sum \infty \frac{( ( - 1 ) ^{(n - 1)} )}{( n ^{3} )}

y^{^{'}} + 2 y = 3

What is (\partial)/(\partial x)(3e^{xy+4}) ?
The answer to (\partial)/(\partial x)(3e^{xy+4}) is 3e^{xy+4}y