What is the derivative of 1/((x-3^2)) ?

The derivative of 1/((x-3^2)) is -2/((x-3)^3)

What is the first derivative of 1/((x-3^2)) ?

The first derivative of 1/((x-3^2)) is -2/((x-3)^3)

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\frac{d}{d x} (\frac{1}{( x - 3 ) ^{2}})

- \frac{2}{( x - 3 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x - 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

= - \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= - \frac{2}{( x - 3 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x - 3 ) ^{3}}

\int_{- 1}^{3} e^{2 x} d x

\int \frac{1}{49 x ^{2} - 64} d x

\frac{d}{d x} (- b sin (x))

\frac{d}{d t} (\frac{t}{( t - 1 ) ^{2}})

n = 0 \sum \infty \frac{n}{n ^{3} + 4}

What is the derivative of 1/((x-3^2)) ?
The derivative of 1/((x-3^2)) is -2/((x-3)^3)
What is the first derivative of 1/((x-3^2)) ?
The first derivative of 1/((x-3^2)) is -2/((x-3)^3)