What is the sum from n=0 to infinity of (5/2)^n ?

The sum from n=0 to infinity of (5/2)^n is diverges

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sum from n=0 to infinity of (5/2)^n

n = 0 \sum \infty (\frac{5}{2})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{5}{2})^{n}

Apply Series Geometric Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{3 ^{n} + 5}

\frac{\partial}{\partial x} (2 x + 4 y)

n = 1 \sum \infty \frac{6}{π \cdot n}

\int x^{- \frac{3}{4}} + 4 e^{x} d x

What is the sum from n=0 to infinity of (5/2)^n ?
The sum from n=0 to infinity of (5/2)^n is diverges