What is the derivative of (3-2x-x^2/(x^2-6)) ?

The derivative of (3-2x-x^2/(x^2-6)) is (2x^2+6x+12)/((x^2-6)^2)

What is the first derivative of (3-2x-x^2/(x^2-6)) ?

The first derivative of (3-2x-x^2/(x^2-6)) is (2x^2+6x+12)/((x^2-6)^2)

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\frac{d}{d x} (\frac{3 - 2 x - x ^{2}}{x ^{2} - 6})

\frac{2 x ^{2} + 6 x + 12}{( x ^{2} - 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 - 2 x - x ^{2}}{x ^{2} - 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 - 2 x - x ^{2} ) ( x ^{2} - 6 ) - \frac{d}{d x} ( x ^{2} - 6 ) ( 3 - 2 x - x ^{2} )}{( x ^{2} - 6 ) ^{2}}

\frac{d}{d x} (3 - 2 x - x^{2}) = - 2 x - 2

\frac{d}{d x} (x^{2} - 6) = 2 x

= \frac{( - 2 x - 2 ) ( x ^{2} - 6 ) - 2 x ( 3 - 2 x - x ^{2} )}{( x ^{2} - 6 ) ^{2}}

Expand

(- 2 x - 2) (x^{2} - 6) - 2 x (3 - 2 x - x^{2}) : 2 x^{2} + 6 x + 12

= \frac{2 x ^{2} + 6 x + 12}{( x ^{2} - 6 ) ^{2}}

\frac{d}{d x} (x^{4} + 4 x^{2})

\int - 3 cos (3 x) d x

\int 5^{2 x} d x

\frac{d}{d x} ((ln (2 x))^{2})

\int (x^{2} - 2 x + 4) d x

What is the derivative of (3-2x-x^2/(x^2-6)) ?
The derivative of (3-2x-x^2/(x^2-6)) is (2x^2+6x+12)/((x^2-6)^2)
What is the first derivative of (3-2x-x^2/(x^2-6)) ?
The first derivative of (3-2x-x^2/(x^2-6)) is (2x^2+6x+12)/((x^2-6)^2)