What is the derivative of x^4+4x^2 ?

The derivative of x^4+4x^2 is 4x^3+8x

What is the first derivative of x^4+4x^2 ?

The first derivative of x^4+4x^2 is 4x^3+8x

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\frac{d}{d x} (x^{4} + 4 x^{2})

4 x^{3} + 8 x

Solution steps

\frac{d}{d x} (x^{4} + 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{2}) = 8 x

= 4 x^{3} + 8 x

\int - 3 cos (3 x) d x

\int 5^{2 x} d x

\frac{d}{d x} ((ln (2 x))^{2})

\int (x^{2} - 2 x + 4) d x

(2 x^{2} - y e^{x}) d x - e^{x} d y = 0

What is the derivative of x^4+4x^2 ?
The derivative of x^4+4x^2 is 4x^3+8x
What is the first derivative of x^4+4x^2 ?
The first derivative of x^4+4x^2 is 4x^3+8x