What is the derivative of 1+3^x ?

The derivative of 1+3^x is ln(3)*3^x

What is the first derivative of 1+3^x ?

The first derivative of 1+3^x is ln(3)*3^x

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\frac{d}{d x} (1 + 3^{x})

ln (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (1 + 3^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3^{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= 0 + 3^{x} ln (3)

Simplify

= ln (3) \cdot 3^{x}

x \to 2 π lim (x)

sec^{2} (θ) - 3

\frac{d}{d x} (\frac{x ^{2} - 4}{x ^{2} + 1})

y = 220 + 65 x

What is the derivative of 1+3^x ?
The derivative of 1+3^x is ln(3)*3^x
What is the first derivative of 1+3^x ?
The first derivative of 1+3^x is ln(3)*3^x