What is (\partial)/(\partial x)(2/x-x) ?

The answer to (\partial)/(\partial x)(2/x-x) is -2/(x^2)-1

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(\partial)/(\partial x)(2/x-x)

\frac{\partial}{\partial x} (\frac{2}{x} - x)

- \frac{2}{x ^{2}} - 1

Solution steps

\frac{\partial}{\partial x} (\frac{2}{x} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{2}{x}) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

\frac{\partial}{\partial x} (x) = 1

= - \frac{2}{x ^{2}} - 1

\frac{d}{d x} (- 8 e^{- 2 x})

x \to 4 lim (2 \cdot e^{\frac{2}{x - 4}})

x \to 0 lim ((- 3) sin (7 x))

y^{^{''}} - 1 = 0

\int ln ∣ x ∣ \cdot 1 d x

What is (\partial)/(\partial x)(2/x-x) ?
The answer to (\partial)/(\partial x)(2/x-x) is -2/(x^2)-1