What is the integral from 0 to 1 of (x^2) ?

The integral from 0 to 1 of (x^2) is 1/3

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integral from 0 to 1 of (x^2)

\int_{0}^{1} (x^{2}) d x

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

\int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\frac{2}{2 s ^{2} + 1}

\frac{\partial}{\partial y} (y - 2 x - 2)

y = \frac{1}{x - 3}

\int \frac{( x ^{2} + 1 )}{( x - 9 ) ( x - 8 ) ^{2}} d x

\int x cos (8 x^{2}) d x

What is the integral from 0 to 1 of (x^2) ?
The integral from 0 to 1 of (x^2) is 1/3