What is the (dy)/(dx)=(y^2-1)/(x^2-1),y(2)=-1 ?

The (dy)/(dx)=(y^2-1)/(x^2-1),y(2)=-1 is 0

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(dy)/(dx)=(y^2-1)/(x^2-1),y(2)=-1

\frac{d y}{d x} = \frac{y ^{2} - 1}{x ^{2} - 1}, y (2) = - 1

0

Solution steps

\frac{y ^{2} - 1}{x ^{2} - 1} = \frac{y ^{2} - 1}{x ^{2} - 1}

Constant function results in a constant

y (2) = - 1

= \frac{( - 1 ) ^{2} - 1}{x ^{2} - 1}

Expand

\frac{( - 1 ) ^{2} - 1}{x ^{2} - 1} : 0

= 0

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What is the (dy)/(dx)=(y^2-1)/(x^2-1),y(2)=-1 ?
The (dy)/(dx)=(y^2-1)/(x^2-1),y(2)=-1 is 0