What is derivative of y(X)=-3^X ?

The answer to derivative of y(X)=-3^X is (dy}{dx}=\frac{-ln(3)*3^x-y)/x

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derivative of y(X)=-3^X

derivative of

y = - 3^{x}

\frac{d y}{d x} = \frac{- ln ( 3 ) \cdot 3 ^{x} - y}{x}

Solution steps

y x = - 3^{x}

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = - 3^{x} ln (3)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- ln ( 3 ) \cdot 3 ^{x} - y}{x}

\frac{d y}{d x} = \frac{- ln ( 3 ) \cdot 3 ^{x} - y}{x}

x \to 3 lim (2 x^{2} + 1)

\frac{d y}{d x} + \frac{2}{x} y = x^{2} y^{3}

\frac{d}{d x} (3 x^{2} + 4 x + 2)

\frac{d}{d x} (1 - (1 - (\frac{x}{y ( x , s )})^{s})^{n})

n = 0 \sum \infty \frac{1}{n + 3}

What is derivative of y(X)=-3^X ?
The answer to derivative of y(X)=-3^X is (dy}{dx}=\frac{-ln(3)*3^x-y)/x