What is the derivative of x^2+6x-1 ?

The derivative of x^2+6x-1 is 2x+6

What is the first derivative of x^2+6x-1 ?

The first derivative of x^2+6x-1 is 2x+6

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\frac{d}{d x} (x^{2} + 6 x - 1)

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (1) = 0

= 2 x + 6 - 0

Simplify

= 2 x + 6

x \to 0 lim (\frac{8 ^{x} - 7 ^{x}}{x})

\frac{d}{d x} (tan^{s e c (\frac{1}{x})} (\frac{1}{x}))

f (x) = x^{4} - 6 x^{3}

\int 7 x^{2} + x x d x

\frac{d y}{d t} = 6 y + cos (3 t), y (0) = \frac{28}{15}

What is the derivative of x^2+6x-1 ?
The derivative of x^2+6x-1 is 2x+6
What is the first derivative of x^2+6x-1 ?
The first derivative of x^2+6x-1 is 2x+6