What is the derivative of f(x)=e^x-e^{-x} ?

The derivative of f(x)=e^x-e^{-x} is e^x+e^{-x}

What is the first derivative of f(x)=e^x-e^{-x} ?

The first derivative of f(x)=e^x-e^{-x} is e^x+e^{-x}

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derivative of

f (x) = e^{x} - e^{- x}

e^{x} + e^{- x}

Solution steps

\frac{d}{d x} (e^{x} - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= e^{x} - (- e^{- x})

Simplify

= e^{x} + e^{- x}

\frac{\partial}{\partial x} (1 0^{- 2 x})

y^{^{'}} = \frac{x ^{3} y ^{3} + 2 x ^{3}}{y ^{2}}

x \to 7 + lim (\frac{6 x}{x - 7})

\frac{\partial}{\partial y} (- y^{2})

(3.6) (- 5.2)

What is the derivative of f(x)=e^x-e^{-x} ?
The derivative of f(x)=e^x-e^{-x} is e^x+e^{-x}
What is the first derivative of f(x)=e^x-e^{-x} ?
The first derivative of f(x)=e^x-e^{-x} is e^x+e^{-x}