What is the solution for (2x+2/y)+((2x^2)/y+(2x)/(y^2))y^'=0 ?

The solution for (2x+2/y)+((2x^2)/y+(2x)/(y^2))y^'=0 is y=(c_{1})/x

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(2x+2/y)+((2x^2)/y+(2x)/(y^2))y^'=0

(2 x + \frac{2}{y}) + (\frac{2 x ^{2}}{y} + \frac{2 x}{y ^{2}}) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(2 x + \frac{2}{y}) + (\frac{2 x ^{2}}{y} + \frac{2 x}{y ^{2}}) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\frac{d}{d x} (x (x + 1))

\int_{0}^{4} f (x) d x

(x - 2) y^{^{'}} + y = 3 x^{2} + 2 x

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{4}}

x + 3 y = 34, x + 6 = y^{2}

What is the solution for (2x+2/y)+((2x^2)/y+(2x)/(y^2))y^'=0 ?
The solution for (2x+2/y)+((2x^2)/y+(2x)/(y^2))y^'=0 is y=(c_{1})/x