What is the integral of (x^2-1)/(x^2-1) ?

The integral of (x^2-1)/(x^2-1) is x+C

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integral of (x^2-1)/(x^2-1)

\int \frac{x ^{2} - 1}{x ^{2} - 1} d x

x + C

Solution steps

\int \frac{x ^{2} - 1}{x ^{2} - 1} d x

Simplify

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

\int x^{2} \cdot ab \cdot e^{- ab x + ab c} d x

\frac{\partial}{\partial y} (e^{x^{2}} + 2 x y)

\int_{0}^{37} x^{2} d x

\frac{3}{4 x + 1}

\frac{d}{d x} (\frac{2 x}{x ^{2} + 1})

What is the integral of (x^2-1)/(x^2-1) ?
The integral of (x^2-1)/(x^2-1) is x+C