What is the derivative of (1-5t)/(6+t) ?

The derivative of (1-5t)/(6+t) is -(31)/((6+t)^2)

What is the first derivative of (1-5t)/(6+t) ?

The first derivative of (1-5t)/(6+t) is -(31)/((6+t)^2)

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derivative of

\frac{1 - 5 t}{6 + t}

- \frac{31}{( 6 + t ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{1 - 5 t}{6 + t})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d t} ( 1 - 5 t ) ( 6 + t ) - \frac{d}{d t} ( 6 + t ) ( 1 - 5 t )}{( 6 + t ) ^{2}}

\frac{d}{d t} (1 - 5 t) = - 5

\frac{d}{d t} (6 + t) = 1

= \frac{( - 5 ) ( 6 + t ) - 1 \cdot ( 1 - 5 t )}{( 6 + t ) ^{2}}

Simplify

\frac{( - 5 ) ( 6 + t ) - 1 \cdot ( 1 - 5 t )}{( 6 + t ) ^{2}} : - \frac{31}{( 6 + t ) ^{2}}

= - \frac{31}{( 6 + t ) ^{2}}

\frac{\partial}{\partial x} (x^{4} - a x^{2} + a^{2})

n = 1 \sum \infty n^{\frac{3}{2}}

t \cdot \frac{d y}{d t} = t^{3} + 11 t^{3} y

2 x^{5} + 3 x^{3} - 3

x \to \infty lim (- 3^{- x})

What is the derivative of (1-5t)/(6+t) ?
The derivative of (1-5t)/(6+t) is -(31)/((6+t)^2)
What is the first derivative of (1-5t)/(6+t) ?
The first derivative of (1-5t)/(6+t) is -(31)/((6+t)^2)