What is the integral of x^{18}e^{x^{19}} ?

The integral of x^{18}e^{x^{19}} is 1/19 e^{x^{19}}+C

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integral of x^{18}e^{x^{19}}

\int x^{18} e^{x^{19}} d x

\frac{1}{19} e^{x^{19}} + C

Solution steps

\int x^{18} e^{x^{19}} d x

Apply u-substitution

: \int \frac{1}{19} d u

= \int \frac{1}{19} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{19} u

Substitute back

u = e^{x^{19}}

= \frac{1}{19} e^{x^{19}}

Add a constant to the solution

= \frac{1}{19} e^{x^{19}} + C

y^{^{''}} + y = 4 x + 10

x y^{^{'}} = y + x^{2} - y^{2}

x \to 1 - lim (\frac{5}{x ^{3} - 1})

f (x) = 4 x^{2} - 2 x + 1, at x = 3

1 + e^{x}

What is the integral of x^{18}e^{x^{19}} ?
The integral of x^{18}e^{x^{19}} is 1/19 e^{x^{19}}+C