What is the solution for t((dy)/(dt))+33y= 1/t ?

The solution for t((dy)/(dt))+33y= 1/t is y= 1/(32t)+(c_{1})/(t^{33)}

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t((dy)/(dt))+33y= 1/t

t (\frac{d y}{d t}) + 33 y = \frac{1}{t}

y = \frac{1}{32 t} + \frac{c _{1}}{t ^{33}}

Solution steps

t (\frac{d y}{d t}) + 33 y = \frac{1}{t}

Solve linear ODE:

y = \frac{1}{32 t} + \frac{c _{1}}{t ^{33}}

y = \frac{1}{32 t} + \frac{c _{1}}{t ^{33}}

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What is the solution for t((dy)/(dt))+33y= 1/t ?
The solution for t((dy)/(dt))+33y= 1/t is y= 1/(32t)+(c_{1})/(t^{33)}