What is area 3e^x,3xe^{x^2},0,1 ?

The answer to area 3e^x,3xe^{x^2},0,1 is 3(e-1)-(3(e-1))/2

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area 3e^x,3xe^{x^2},0,1

area

3 e^{x}, 3 x e^{x^{2}}, 0, 1

3 (e - 1) - \frac{3 ( e - 1 )}{2}

Decimal Notation

2.57742 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 3 e^{x} - 3 x e^{x^{2}} d x

Solve

\int_{0}^{1} 3 e^{x} - 3 x e^{x^{2}} d x : 3 (e - 1) - \frac{3 ( e - 1 )}{2}

The area is:

= 3 (e - 1) - \frac{3 ( e - 1 )}{2}

\int 3 t sin (t) cos (t) d t

(x^{4} + 2 x^{3} y^{2}) d x + x^{4} y d y = 0

\frac{d y}{d t} - 2 y = 3 e^{- 2 t}, y (0) = 10

\frac{\partial}{\partial x} (x^{3} + 2 x^{2} y + x + 2 y)

\int \frac{1}{X ^{2}} D X d X

What is area 3e^x,3xe^{x^2},0,1 ?
The answer to area 3e^x,3xe^{x^2},0,1 is 3(e-1)-(3(e-1))/2