What is the solution for y^{''}-6y^'+9y=t^{-9}e^{3t} ?

The solution for y^{''}-6y^'+9y=t^{-9}e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(e^{3t})/(56t^7)

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y^{''}-6y^'+9y=t^{-9}e^{3t}

y^{^{''}} - 6 y^{^{'}} + 9 y = t^{- 9} e^{3 t}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{56 t ^{7}}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = t^{- 9} e^{3 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{56 t ^{7}}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{56 t ^{7}}

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\frac{d ^{2} y}{d x ^{2}} - b y = 0

What is the solution for y^{''}-6y^'+9y=t^{-9}e^{3t} ?
The solution for y^{''}-6y^'+9y=t^{-9}e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(e^{3t})/(56t^7)